Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapter 9 Review Problem Set: 1

Answer

8

Work Step by Step

Recall the following rule: $(a^{b})^{c}=a^{bc}$ Thus, we obtain: $\sqrt {64}=\sqrt {8^{2}}=(8^{2})^{\frac{1}{2}}=8^{1}=8$
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