## Elementary Algebra

Published by Cengage Learning

# Chapter 9 - Roots and Radicals - Chapter 9 Review Problem Set - Page 430: 18

#### Answer

$\dfrac{5\sqrt{6}}{6}$

#### Work Step by Step

Using the properties of radicals, the given expression, $\dfrac{5\sqrt{2}}{2\sqrt{3}} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{5\sqrt{2}}{2\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}} \\\\= \dfrac{5\sqrt{6}}{2\cdot3} \\\\= \dfrac{5\sqrt{6}}{6} .\end{array}

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