Answer
$40$
Work Step by Step
Recall the following rule:
$(a^{b})^{c}=a^{bc}$
Thus, we obtain:
$\sqrt {1600}=\sqrt {40\times40}=\sqrt {40^{2}}=(40^{2})^{1/2}=40^{1}=40$
Elementary Algebra
by Kaufmann, Jerome; Schwitters, Karen;
Published by
Cengage Learning
ISBN 10:
1285194055
ISBN 13:
978-1-28519-405-9
Chapter 9 - Roots and Radicals - Chapter 9 Review Problem Set - Page 430: 3
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
