Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapter 9 Review Problem Set - Page 430: 12


$\sqrt[3] 5$

Work Step by Step

We break up the square roots, and then we cancel out common factors in the numerator and the denominator of the fraction to obtain: $\frac{\sqrt[3] {40}}{\sqrt[3] 8}$ =$\frac{\sqrt[3] {8\times5}}{\sqrt[3] 8}$ =$\frac{\sqrt[3] {8}\times\sqrt[3] 5}{\sqrt[3] 8}$ =$\frac{1\times\sqrt[3] 5}{1}$ =$\sqrt[3] 5$
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