## Elementary Algebra

$\sqrt[3] 5$
We break up the square roots, and then we cancel out common factors in the numerator and the denominator of the fraction to obtain: $\frac{\sqrt[3] {40}}{\sqrt[3] 8}$ =$\frac{\sqrt[3] {8\times5}}{\sqrt[3] 8}$ =$\frac{\sqrt[3] {8}\times\sqrt[3] 5}{\sqrt[3] 8}$ =$\frac{1\times\sqrt[3] 5}{1}$ =$\sqrt[3] 5$