Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapter 9 Review Problem Set: 12

Answer

$\sqrt[3] 5$

Work Step by Step

We break up the square roots, and then we cancel out common factors in the numerator and the denominator of the fraction to obtain: $\frac{\sqrt[3] {40}}{\sqrt[3] 8}$ =$\frac{\sqrt[3] {8\times5}}{\sqrt[3] 8}$ =$\frac{\sqrt[3] {8}\times\sqrt[3] 5}{\sqrt[3] 8}$ =$\frac{1\times\sqrt[3] 5}{1}$ =$\sqrt[3] 5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.