Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapter 9 Review Problem Set: 37

Answer

$6\sqrt 2$

Work Step by Step

We break the square root into its factors, and then we simplify the factors that are perfect squares: $\sqrt 6\times\sqrt {12}$ =$\sqrt {6\times12}$ =$\sqrt {72}$ =$\sqrt {2\times36}$ =$\sqrt 2\times\sqrt {36}$ =$\sqrt 2\times6$ =$6\sqrt 2$
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