Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapter 9 Review Problem Set: 21

Answer

$\approx 5.2$

Work Step by Step

Using $\sqrt{3}=1.73$ and the properties of radicals, the value of the given expression, $ \sqrt{27} ,$ to the nearest tenth, is \begin{array}{l}\require{cancel} \sqrt{9\cdot3} \\\\= \sqrt{(3)^2\cdot3} \\\\= 3\sqrt{3} \\\\= 3(1.73) \\\\ \approx 5.2 .\end{array}
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