# Chapter 9 - Roots and Radicals - Chapter 9 Review Problem Set - Page 430: 21

$\approx 5.2$

#### Work Step by Step

Using $\sqrt{3}=1.73$ and the properties of radicals, the value of the given expression, $\sqrt{27} ,$ to the nearest tenth, is \begin{array}{l}\require{cancel} \sqrt{9\cdot3} \\\\= \sqrt{(3)^2\cdot3} \\\\= 3\sqrt{3} \\\\= 3(1.73) \\\\ \approx 5.2 .\end{array}

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.