## Elementary Algebra

$\dfrac{-2\sqrt{x}}{5}$
Using the properties of radicals, the given expression, $\dfrac{-2\sqrt{x^2y}}{5\sqrt{xy}} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{-2}{5}\sqrt{\dfrac{x^2y}{xy}} \\\\= \dfrac{-2}{5}\sqrt{\dfrac{\cancel{xy}\cdot x}{\cancel{xy}}} \\\\= \dfrac{-2}{5}\sqrt{x} \\\\= \dfrac{-2\sqrt{x}}{5} .\end{array} Note that all variables are assumed to have positive values.