## Elementary Algebra

$\approx 1.2$
Using $\sqrt{3}=1.73$ and the properties of radicals, the value of the given expression, $\dfrac{2}{\sqrt{3}} ,$ to the nearest tenth, is \begin{array}{l}\require{cancel} \dfrac{2}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}} \\\\= \dfrac{2\sqrt{3}}{3} \\\\= \dfrac{2(1.73)}{3} \\\\ \approx 1.2 .\end{array}