Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapter 9 Review Problem Set - Page 430: 39



Work Step by Step

We first multiply the separate square roots together to create one square root. Then, we simplify $\sqrt{16}$ because it is a perfect square: $-5\sqrt 8 \times 2\sqrt 2$ =$(-5\times2)\times(\sqrt 8\times\sqrt 2)$ =$(-10)\times(\sqrt {8\times2})$ =$(-10)\times(\sqrt {16})$ =$(-10)\times(\sqrt {4^{2}})$ =$(-10)\times(4)$ =$-40$
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