Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.3 - Adding and Subtracting Algebraic Fractions - Problem Set 7.3 - Page 291: 26



Work Step by Step

By inspection, we see that there is a common denominator of $5x$. Therefore, we obtain: $\frac{4(x-3)}{5x}+\frac{2(x+6)}{5x}$ =$\frac{4(x-3)+2(x+6)}{5x}$ =$\frac{4x-12+2x+12}{5x}$ =$\frac{6x+0}{5x}$ =$\frac{6x}{5x}$ =$\frac{6}{5}$
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