Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.3 - Adding and Subtracting Algebraic Fractions - Problem Set 7.3: 17

Answer

$\frac{3a+8}{3}$

Work Step by Step

By inspection, we see that there is a common denominator of $3$. Therefore, we obtain: $\frac{7a+2}{3}-\frac{4a-6}{3}$ =$\frac{(7a+2)-(4a-6)}{3}$ =$\frac{7a+2-4a+6}{3}$ =$\frac{3a+8}{3}$
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