Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.3 - Adding and Subtracting Algebraic Fractions - Problem Set 7.3: 20

Answer

$\frac{(4n-3)}{5}$

Work Step by Step

By inspection, we see that there is a common denominator of $10$. Therefore, we obtain: $\frac{2n-5}{10}+\frac{6n-1}{10}$ =$\frac{2n-5+6n-1}{10}$ =$\frac{8n-6}{10}$ =$\frac{2(4n-3)}{10}$ =$\frac{(4n-3)}{5}$
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