Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.3 - Adding and Subtracting Algebraic Fractions - Problem Set 7.3 - Page 291: 18



Work Step by Step

By inspection, we see that there is a common denominator of $6$. Therefore, we obtain: $\frac{9a-1}{6}-\frac{4a-2}{6}$ =$\frac{(9a-1)-(4a-2)}{6}$ =$\frac{9a-1-4a+2}{6}$ =$\frac{5a+1}{6}$
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