Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.3 - Adding and Subtracting Algebraic Fractions - Problem Set 7.3 - Page 291: 14

Answer

$2$

Work Step by Step

By inspection, we see that there is a common denominator of $x$. Therefore, we obtain: $\frac{2x+3}{x}-\frac{3}{x}$ =$\frac{(2x+3)-(3)}{x}$ =$\frac{2x+3-3}{x}$ =$\frac{2x}{x}$ =$2$
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