Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.3 - Adding and Subtracting Algebraic Fractions - Problem Set 7.3: 21

Answer

$-n-1$

Work Step by Step

By inspection, we see that there is a common denominator of $6$. Therefore, we obtain: $\frac{3n-7}{6}-\frac{9n-1}{6}$ =$\frac{3n-7-(9n-1)}{6}$ =$\frac{3n-7-9n+1}{6}$ =$\frac{-6n-6}{6}$ =$\frac{6(-n-1)}{6}$ =$-n-1$
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