Answer
$\frac{12t-6}{7}$
Work Step by Step
By inspection, we see that there is a common denominator of $7$. Therefore, we obtain:
$\frac{4t-1}{7}+\frac{8t-5}{7}$
=$\frac{(4t-1)+(8t-5)}{7}$
=$\frac{4t+8t-1-5}{7}$
=$\frac{12t-6}{7}$
Elementary Algebra
by Kaufmann, Jerome; Schwitters, Karen;
Published by
Cengage Learning
ISBN 10:
1285194055
ISBN 13:
978-1-28519-405-9
Chapter 7 - Algebraic Fractions - 7.3 - Adding and Subtracting Algebraic Fractions - Problem Set 7.3 - Page 291: 16
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