Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.3 - Adding and Subtracting Algebraic Fractions - Problem Set 7.3 - Page 291: 16



Work Step by Step

By inspection, we see that there is a common denominator of $7$. Therefore, we obtain: $\frac{4t-1}{7}+\frac{8t-5}{7}$ =$\frac{(4t-1)+(8t-5)}{7}$ =$\frac{4t+8t-1-5}{7}$ =$\frac{12t-6}{7}$
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