Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.3 - Adding and Subtracting Algebraic Fractions - Problem Set 7.3 - Page 291: 25



Work Step by Step

By inspection, we see that there is a common denominator of $4x$. Therefore, we obtain: $\frac{3(x+2)}{4x}+\frac{6(x-1)}{4x}$ =$\frac{3(x+2)+6(x-1)}{4x}$ =$\frac{3x+6+6x-6}{4x}$ =$\frac{9x+0}{4x}$ =$\frac{9x}{4x}$ =$\frac{9}{4}$
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