Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.3 - Adding and Subtracting Algebraic Fractions - Problem Set 7.3 - Page 291: 19



Work Step by Step

By inspection, we see that there is a common denominator of $8$. Therefore, we obtain: $\frac{4n+3}{8}+\frac{6n+5}{8}$ =$\frac{4n+3+6n+5}{8}$ =$\frac{10n+8}{8}$ =$\frac{2(5n+4)}{8}$ =$\frac{(5n+4)}{4}$
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