Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.3 - Adding and Subtracting Algebraic Fractions - Problem Set 7.3 - Page 291: 12



Work Step by Step

By inspection, we see that there is a common denominator of $(x+4)$. Therefore, we obtain: $\frac{8}{x+4}-\frac{10}{x+4}$ =$\frac{8-(10)}{x+4}$ =$\frac{8-10}{x+4}$ =$\frac{-2}{x+4}$ =$-\frac{2}{x+4}$
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