#### Answer

$392$

#### Work Step by Step

Factor each number completely to have:
$49= 7 \cdot 7
\\56 = 2 \cdot 2 \cdot 2 \cdot 7$
The different factors that appear in the prime factorization of the given numbers are 2 and 7.
The maximum number of times that each unique factor appears in the factorization is:
For 2: three times
For 7: two times
The least common multiple will have three 2s and two 7s.
Thus, the least common multiple of the given numbers is:
$=2 \cdot 2\cdot 2 \cdot 7 \cdot 7
\\= 392$