# Chapter 1 - Some Basic Concepts of Arithmetic and Algebra - 1.2 - Prime and Composite Numbers - Problem Set 1.2 - Page 13: 80

$462$

#### Work Step by Step

Factor each number completely to obtain: $42= 2\cdot 3\cdot 7 \\66 = 2 \cdot 3 \cdot 11$ The different factors that appear in the prime factorization of the given numbers are 2, 3, 7, and 11. The maximum number of times that each unique factor appears in the factorization is: For 2: once For 3: once For 7: once For 11: once The least common multiple will have one 2, one 3, one 7, and one 11. Thus, the least common multiple of the given numbers is: $=2 \cdot 3\cdot 7 \cdot 11 \\= 462$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.