## Elementary Algebra

$48$
Factor each number completely to obtain: $16= 2\cdot 2\cdot 2 \cdot 2 \\12 = 2 \cdot 2 \cdot 3$ The different factors that appear in the prime factorization of the given numbers are 2 and 3. The maximum number of times that each unique factor appears in the factorization is: For 2: four times For 3: once The least common multiple will have four 2s and one 3. Thus, the least common multiple of the given numbers is: $=2 \cdot 2\cdot 2 \cdot 2 \cdot 3 \\= 48$