## Elementary Algebra

Published by Cengage Learning

# Chapter 1 - Some Basic Concepts of Arithmetic and Algebra - 1.2 - Prime and Composite Numbers - Problem Set 1.2 - Page 13: 59

#### Answer

$120 = 2 \cdot 2 \cdot 2 \cdot 3 \cdot 5$

#### Work Step by Step

The number is even so it is divisible by 2. Factor out 2 to obtain: $120= 2 \cdot 60$ 60 is even, so factor out 2 to obtain: $120 = 2 \cdot 2 \cdot 30$ 30 is even, so factor out 2 to obtain: $120 = 2 \cdot 2 \cdot 2 \cdot 15$ 15 is divisible by 3 so factor out 3 to obtain: $120 = 2 \cdot 2 \cdot 2 \cdot 3 \cdot 5$

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