Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 1 - Some Basic Concepts of Arithmetic and Algebra - 1.2 - Prime and Composite Numbers - Problem Set 1.2 - Page 13: 58

Answer

$144=2\times2\times3\times2\times2\times3$

Work Step by Step

Start with the original number, 144. 144 can be divided by 12, so factor it out: $12\times12$ 12 can be divided by 4 and 3, so factor these out of each 12. $(4\times3)\times(4\times3)$ 3 is a prime number, so there is no more factoring of it, but 4 is composite, so factor a two out of each four: $[(2\times2)\times3]\times[(2\times2)\times3]$ Make sure that the expression equals 144. $4\times3\times4\times3$ $12\times12$ $144$
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