Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 1 - Some Basic Concepts of Arithmetic and Algebra - 1.2 - Prime and Composite Numbers - Problem Set 1.2: 78

Answer

$36$

Work Step by Step

Factor each number completely to obtain: $9= 3 \cdot 3 \\12 = 2 \cdot 2 \cdot 3$ The different factors that appear in the prime factorization of the given numbers are 2 and 3. The maximum number of times that each unique factor appears in the factorization is: For 2: two times For 3: two times The least common multiple will have two 2s and two 3s. Thus, the least common multiple of the given numbers is: $=2 \cdot 2\cdot 3 \cdot 3 \\= 36$
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