Answer
$76=2\times2\times19$
Work Step by Step
Since the last digit of 76 is an even number, 76 is divisible by 2. When we divide 76 by 2, we get 38. 38 is further divisible by 2, and 38 divided by 2 is 19. 19 is not divisible by any number except 1 and is therefore a prime number. Since 2, 2, and 19 are prime factors, the prime factorization of 76 is $2\times2\times19$.
