## Elementary Algebra

Published by Cengage Learning

# Chapter 1 - Some Basic Concepts of Arithmetic and Algebra - 1.2 - Prime and Composite Numbers - Problem Set 1.2 - Page 13: 48

#### Answer

$7\times7\times3\times3$

#### Work Step by Step

Since the sum of the digits of $441$ add up to $9$, it is divisible by $9$. When we divide $441$ by $9$ we get $49$. $49$ is the perfect square of $7$, and can be broken down into prime factors $7\times7$. $9$ can be broken down into prime factors $3\times3$. Since $3$ and $7$ are prime numbers, the prime factorization of $441$ is $7\times7\times3\times3$

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