Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 1 - Some Basic Concepts of Arithmetic and Algebra - 1.2 - Prime and Composite Numbers - Problem Set 1.2 - Page 13: 53

Answer

$36=3\times2\times3\times2$

Work Step by Step

The number 36 is a perfect square of the number 6. Therefore, $36=6\times6$. Each of these sixes can be broken down into prime factors, $3\times2$. This leaves us with $36=3\times2\times3\times2$
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