Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 1 - Some Basic Concepts of Arithmetic and Algebra - 1.2 - Prime and Composite Numbers - Problem Set 1.2: 57

Answer

$56=7\times2\times2\times2$

Work Step by Step

When we divide $56$ by $7$, we get $8$. This gives us $56=7\times8$. Since $8$ is the perfect cube of $2$, a prime number, it can be broken down as $2\times2\times2$. When we plug this in for 8, we get $56=7\times2\times2\times2$
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