Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 10 - The Laplace Transform and Some Elementary Applications - 10.9 The Convolution Integral - Problems - Page 716: 16

Answer

See below

Work Step by Step

Given: $F(s)=\frac{1}{s+1}\\ G(s)=\frac{1}{s}$ Obtain: $L^{-1}[F(s)* G(s)]=L^{-1}[\frac{1}{s+1}.\frac{1}{s}]\\ =L^{-1}[\frac{1}{s+1}].L^{-1}[\frac{1}{s}]\\ =e^{-t}.1\\ =\int^t_0 e^{-(t-x)}dx\\ =e^{-t}\int^t_0 e^x dx\\ =e^{-t}\begin{bmatrix} e^x \end{bmatrix}^t_0\\ =1-e^{-t}$
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