College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Chapter P Review - Exercises - Page 77: 94


$\{x|x\neq-3$ and $x\neq 3\}$

Work Step by Step

We know that $\displaystyle \frac{2x}{x^{2}-9}$ is undefined whenever the denominator is 0, so: $x^2-9=(x+3)(x-3)=0$ $x=3, x=-3$ Thus the domain is: $\{x|x\neq-3$ and $x\neq 3\}$
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