## College Algebra 7th Edition

We solve the equation: $\displaystyle \frac{x+1}{x-1}=\frac{3x}{3x-6}$ $\displaystyle \frac{x+1}{x-1}=\frac{3x}{3(x-2)}$ $\displaystyle \frac{x+1}{x-1}=\frac{x}{x-2}$ First we cross-multiply: $(x+1)(x-2)=x(x-1)$ And distribute: $x^{2}-x-2=x^{2}-x$ And combine like terms: $x^{2}-x^{2}-x+x-2=0$ $-2=0$ Since we get a nonsensical equation, there are no solutions.