College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Chapter P Review - Exercises - Page 77: 107



Work Step by Step

We solve for $x$: $\displaystyle \frac{1}{3}x-\frac{1}{2}=2$ Multiplying both sides by $6$, we get: $2x-3=12$ $2x=12+3=15$ $x=\frac{15}{2}$
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