College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Chapter P Review - Exercises: 60

Answer

$2y^2(y^2+4)(y+2)(y-2)$

Work Step by Step

Factor out the GCF $2y^2$ to obtain: $=2y^2(y^4-16)$ Since $y^4=(y^2)^2$ and $16=4^2$, the expression above is equivalent to: $=2y^2[(y^2)^2-4^2]$ Factor the difference of two squares using the formula $a^2-b^2=(a+b)(a-b)$ where $a=y^2$ and $b=4$ to obtain: $=2y^2(y^2+4)(y^2-4) \\=2y^2(y^2+4)(y^2-2^2)$ Factor the difference of two squares with $a=y$ and $b=2$ to obtain: $=2y^2(y^2+4)(y+2)(y-2)$
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