## College Algebra 7th Edition

$(x-2)(4x^2+3)$
Group the first two terms and the last two terms to obtain: $=(4x^3-8x^2)+(3x-6)$ Factor out the GCF in each group ($4x^2$ in the first and $3$ in the second) to obtain: $=4x^2(x-2) + 3(x-2)$ Factor out the GCF $x-2$ to obtain: $=(x-2)(4x^2+3)$