## College Algebra 7th Edition

$x=-\frac{3}{20}$
We solve the equation: $\displaystyle \frac{2}{3}x+\frac{3}{5}=\frac{1}{5}-2x$ First, we multiply both sides by 15: $10x+9=3-30x$ Then we solve for $x$: $10x+30x=3-9$ $40x=-6$ $x=-\frac{6}{40}=-\frac{3}{20}$