Answer
$x=1$
Work Step by Step
$(x+2)^{2}=(x-4)^{2}$
$x^2+4x+4=x^2-8x+16$
$x^2-x^2+4x+8x+4-16=0$
$12x-12=0$
$12x=12$
$x=12/12=1$
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