College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Chapter P Review - Exercises: 79

Answer

$\dfrac{x^2+x-1}{x+1}$

Work Step by Step

The LCD of the rational expressions is $x+1$. Make the expressions similar using their LCD to obtain: $=\dfrac{x(x+1)}{x+1} - \dfrac{1}{x+1} \\=\dfrac{x(x)+x(1)}{x+1}- \dfrac{1}{x+1} \\=\dfrac{x^2+x}{x+1}-\dfrac{1}{x+1}$ Subtract the numerators together and copy the denominator to obtain: $=\dfrac{x^2+x-1}{x+1}$
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