College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Chapter P Review - Exercises - Page 77: 112



Work Step by Step

We solve the equation: $\displaystyle \frac{x}{x+2}-3=\frac{1}{x+2}$ First we multiply both sides by $x+2$: $x-3(x+2)=1$ Next we distribute: $x-3x-6=1$ And solve for $x$: $-2x=7$ $x=-\frac{7}{2}$
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