## College Algebra 7th Edition

$x=-\frac{7}{2}$
We solve the equation: $\displaystyle \frac{x}{x+2}-3=\frac{1}{x+2}$ First we multiply both sides by $x+2$: $x-3(x+2)=1$ Next we distribute: $x-3x-6=1$ And solve for $x$: $-2x=7$ $x=-\frac{7}{2}$