College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.6 - The Binomial Theorem - 8.6 Exercises: 7

Answer

$(x+ \frac{1}{x})^{4}=x^{4}+4x^{2}+6+\frac{4}{x^{2}}+\frac{1}{x^{4}}$

Work Step by Step

We use the values from the 4th row of Pascal's Triangle to find the coefficients: $(x+ \frac{1}{x})^{4}=x^{4}+4x^{3}(\frac{1}{x})^1+6x^{2}(\frac{1}{x})^{2}+4x(\frac{1}{x})^{3}+(\frac{1}{x})^{4}=x^{4}+4x^{2}+6+\frac{4}{x^{2}}+\frac{1}{x^{4}}$
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