## College Algebra 7th Edition

$\left(\begin{array}{l} n\\ k \end{array}\right)=\frac{n!}{k!(n-k)!}$ $\left(\begin{array}{l} 4\\ 3 \end{array}\right)=\frac{4!}{3!1!}=4$
The binomial coefficients can be calculated directly using the formula ___ $\left(\begin{array}{l} n\\ k \end{array}\right)=\frac{n!}{k!(n-k)!}$ ___. So ___ $\left(\begin{array}{l} 4\\ 3 \end{array}\right)=\frac{4!}{3!1!}=4$ ___.