College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.6 - The Binomial Theorem - 8.6 Exercises: 3

Answer

$\left(\begin{array}{l} n\\ k \end{array}\right)=\frac{n!}{k!(n-k)!}$ $\left(\begin{array}{l} 4\\ 3 \end{array}\right)=\frac{4!}{3!1!}=4$

Work Step by Step

The binomial coefficients can be calculated directly using the formula ___ $ \left(\begin{array}{l} n\\ k \end{array}\right)=\frac{n!}{k!(n-k)!}$ ___. So ___ $ \left(\begin{array}{l} 4\\ 3 \end{array}\right)=\frac{4!}{3!1!}=4$ ___.
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