#### Answer

$-25x^{47}$

#### Work Step by Step

We find the 2nd term in the expansion of $(x^{2}-\displaystyle \frac{1}{x})^{25}$ by using Binomial Theorem coefficients:
$\left(\begin{array}{l}25\\1\end{array}\right)(x^{2})^{24}(\frac{-1}{x})^1=-25\frac{x^{48}}{x}=-25x^{47}$