College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.6 - The Binomial Theorem - 8.6 Exercises: 38

Answer

$-25x^{47}$

Work Step by Step

We find the 2nd term in the expansion of $(x^{2}-\displaystyle \frac{1}{x})^{25}$ by using Binomial Theorem coefficients: $\left(\begin{array}{l}25\\1\end{array}\right)(x^{2})^{24}(\frac{-1}{x})^1=-25\frac{x^{48}}{x}=-25x^{47}$
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