Answer
Binomial
$(a+b)^{4}=\left(\begin{array}{l}
4\\ 0 \end{array}\right)a^{4}+\left(\begin{array}{l} 4\\ 1 \end{array}\right)a^{3}b+\left(\begin{array}{l} 4\\ 2 \end{array}\right)a^{2}b^{2}+\left(\begin{array}{l} 4\\ 3 \end{array}\right)ab^{3}+\left(\begin{array}{l} 4\\ 4 \end{array}\right)b^{4}$
Work Step by Step
To expand $(a+b)^{n}$ we can use the ___ Binomial___ Theorem. Using this theorem, we find the expansion of $(a+b)^{4}=\left(\begin{array}{l}
4\\ 0 \end{array}\right)a^{4}+\left(\begin{array}{l} 4\\ 1 \end{array}\right)a^{3}b+\left(\begin{array}{l} 4\\ 2 \end{array}\right)a^{2}b^{2}+\left(\begin{array}{l} 4\\ 3 \end{array}\right)ab^{3}+\left(\begin{array}{l} 4\\ 4 \end{array}\right)b^{4}$
