Answer
$100y^{99}$
Work Step by Step
We find the 100th term in the expansion of $(1+y)^{100}$ by using Binomial Theorem coefficients:
$\left(\begin{array}{l}
100\\99\end{array}\right)1^{1}y^{99}=100(1^1)(y^{99})=100y^{99}$
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