College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.6 - The Binomial Theorem - 8.6 Exercises: 37

Answer

$100y^{99}$

Work Step by Step

We find the 100th term in the expansion of $(1+y)^{100}$ by using Binomial Theorem coefficients: $\left(\begin{array}{l} 100\\99\end{array}\right)1^{1}y^{99}=100(1^1)(y^{99})=100y^{99}$
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