## College Algebra 7th Edition

$-4060A^{3}B^{27}$
We find the 28th term in the expansion of $(A-B)^{30}$ by using Binomial Theorem coefficients: $\left(\begin{array}{l} 30\\27\end{array}\right)A^{3}(-B)^{27}=4060(A^{3})(-B^{27})=-4060A^{3}B^{27}$