#### Answer

$-4060A^{3}B^{27}$

#### Work Step by Step

We find the 28th term in the expansion of $(A-B)^{30}$ by using Binomial Theorem coefficients:
$\left(\begin{array}{l}
30\\27\end{array}\right)A^{3}(-B)^{27}=4060(A^{3})(-B^{27})=-4060A^{3}B^{27}$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$-4060A^{3}B^{27}$

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