College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.6 - The Binomial Theorem - 8.6 Exercises: 36

Answer

$-4060A^{3}B^{27}$

Work Step by Step

We find the 28th term in the expansion of $(A-B)^{30}$ by using Binomial Theorem coefficients: $\left(\begin{array}{l} 30\\27\end{array}\right)A^{3}(-B)^{27}=4060(A^{3})(-B^{27})=-4060A^{3}B^{27}$
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