Chapter 8, Sequences and Series - Section 8.6 - The Binomial Theorem - 8.6 Exercises - Page 636: 13

$(2x-3y)^{3}=8x^{3}-36x^{2}y+54xy^{2}-27y^{3}$

We use the values from the 3rd row of Pascal's Triangle to find the coefficients: $(2x-3y)^{3}=(2x)^{3}-3(2x)^{2}(3y)^1+3(2x)^1(3y)^{2}-(3y)^{3}=8x^{3}-36x^{2}y+54xy^{2}-27y^{3}$