College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.6 - The Binomial Theorem - 8.6 Exercises: 20

Answer

$\left(\begin{array}{l} 10\\ 5 \end{array}\right)=252$

Work Step by Step

We evaluate: $\left(\begin{array}{l} 10\\ 5 \end{array}\right)=\frac{10!}{5!5!}=\frac{10*9*8*7*6*5!}{5!*5*4*3*2*1}=\frac{10*9*8*7*6}{5*4*3*2}=\frac{30240}{120}=252$
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