Chapter 2, Functions - Section 2.8 - One-to-One Functions and their Inverses - 2.8 Exercises - Page 263: 68

$f^{-1}(x) = (x - 2)^{2} - 3, x\geq2$

$f(x) = 2 + \sqrt {3 + x}$ $y= 2 + \sqrt {3 + x}$ $y - 2 =\sqrt {3 + x}$ $(y - 2)^{2} = (\sqrt {3 + x})^{2}$ $(y - 2)^{2} = 3 + x$ $x = (y - 2)^{2} - 3$ $f^{-1}(x) = (x - 2)^{2} - 3, x\geq2$