## College Algebra 7th Edition

$f^{-1}(x) = \frac{2x}{x - 3}$
$f(x) = \frac{3x}{x - 2}$ $y = \frac{3x}{x - 2}$ y(x - 2) = 3x yx - 2y = 3x yx - 3x = 2y x(y - 3) = 2y $x = \frac{2y}{y - 3}$ $f^{-1}(x) = \frac{2x}{x - 3}$