## College Algebra 7th Edition

$f^{-1}(x) = \frac{x - 5}{3}$
f(x) = 3x + 5 y = 3x + 5 y - 5 = 3x $\frac{y - 5}{3} = x$ $\frac{x - 5}{3} = f^{-1}(x)$